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Boiling point of a liquid is 50K at 1 atm and delta Hvap = 460.6 cal/mol . What will be its boiling point at 10 atm ? (R = 2cal/K mol)
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SOLVED: Conversion Factors: 1 gal = 231 in³ (exact) 1 atm = 760 torr (exact) 1 cm³ = 1 mL (exact) 1 lb = 453.59237 g (exact) 2.54 cm = 1 in (
1.- Un émbolo de 40 cm de diámetro avanza 5 cm bajo una presión de 10 atm. ¿Cuántas calorías corresponderán a este trabaj
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4 \mathrm{~L} \) - atm is equal to: a. \( 40.50 \mathrm{cal} \) ... - YouTube
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SOLVED: cal 1.987 mol-K 4.184 cal 8.314 K-mol L-atm 0.08206 K-mol 22.41 mol
